Code
# Bivariate Data from USArrests
<- USArrests[,c('Murder','UrbanPop')]
xy 1,]
xy[## Murder UrbanPop
## Alabama 13.2 58
We will now study them in more detail. Suppose we have two discrete variables \(X_{i}\) and \(Y_{i}\). The data for each observation data can be grouped together as a vector \((X_{i}, Y_{i})\).
# Bivariate Data from USArrests
<- USArrests[,c('Murder','UrbanPop')]
xy 1,]
xy[## Murder UrbanPop
## Alabama 13.2 58
Scatterplots are used frequently to summarize the joint relationship between two variables, multiple observations of \((X_{i}, Y_{i})\). They can be enhanced in several ways. As a default, use semi-transparent points so as not to hide any points (and perhaps see if your observations are concentrated anywhere). You can also add other features that help summarize the relationship, although I will defer this until later.
plot(Murder~UrbanPop, USArrests, pch=16, col=grey(0.,.5))
If you have many points, you can also use a 2D histogram instead. https://plotly.com/r/2D-Histogram/.
library(plotly)
<- plot_ly(
fig x = ~UrbanPop, y = ~Assault)
USArrests, <- add_histogram2d(fig, nbinsx=25, nbinsy=25)
fig fig
You can also show the distributions of each variable along each axis.
# Setup Plot
layout( matrix(c(2,0,1,3), ncol=2, byrow=TRUE),
widths=c(9/10,1/10), heights=c(1/10,9/10))
# Scatterplot
par(mar=c(4,4,1,1))
plot(Murder~UrbanPop, USArrests, pch=16, col=rgb(0,0,0,.5))
# Add Marginals
par(mar=c(0,4,1,1))
<- hist(USArrests[,'UrbanPop'], plot=FALSE)
xhist barplot(xhist[['counts']], axes=FALSE, space=0, border=NA)
par(mar=c(4,0,1,1))
<- hist(USArrests[,'Murder'], plot=FALSE)
yhist barplot(yhist[['counts']], axes=FALSE, space=0, horiz=TRUE, border=NA)
We can show how distributions and densities change according to a second (or even third) variable using data splits. E.g.,
# Tailored Histogram
<- c(0,8)
ylim <- seq(min(USArrests[,'Murder'])-1, max(USArrests[,'Murder'])+1, by=1)
xbks
# Also show more information
# Split Data by Urban Population above/below mean
<- mean(USArrests[,'UrbanPop'])
pop_mean <- USArrests[,'UrbanPop']< pop_mean
pop_cut <- USArrests[pop_cut,'Murder']
murder_lowpop <- USArrests[!pop_cut,'Murder']
murder_highpop <- c(low=rgb(0,0,1,.75), high=rgb(1,0,0,.75))
cols
par(mfrow=c(1,2))
hist(murder_lowpop,
breaks=xbks, col=cols[1],
main='Urban Pop >= Mean', font.main=1,
xlab='Murder Arrests',
border=NA, ylim=ylim)
hist(murder_highpop,
breaks=xbks, col=cols[2],
main='Urban Pop < Mean', font.main=1,
xlab='Murder Arrests',
border=NA, ylim=ylim)
It is sometimes it is preferable to show the ECDF instead. And you can glue various combinations together to convey more information all at once
par(mfrow=c(1,2))
# Full Sample Density
hist(USArrests[,'Murder'],
main='Density Function Estimate', font.main=1,
xlab='Murder Arrests',
breaks=xbks, freq=F, border=NA)
# Split Sample Distribution Comparison
<- ecdf(murder_lowpop)
F_lowpop plot(F_lowpop, col=cols[1],
pch=16, xlab='Murder Arrests',
main='Distribution Function Estimates',
font.main=1, bty='n')
<- ecdf(murder_highpop)
F_highpop plot(F_highpop, add=T, col=cols[2], pch=16)
legend('bottomright', col=cols,
pch=16, bty='n', inset=c(0,.1),
title='% Urban Pop.',
legend=c('Low (<= Mean)','High (>= Mean)'))
# Simple Interactive Scatter Plot
# plot(Assault~UrbanPop, USArrests, col=grey(0,.5), pch=16,
# cex=USArrests[,'Murder']/diff(range(USArrests[,'Murder']))*2,
# main='US Murder arrests (per 100,000)')
You can also split data into grouped boxplots in the same way
layout( t(c(1,2,2)))
boxplot(USArrests[,'Murder'], main='',
xlab='All Data', ylab='Murder Arrests')
# K Groups with even spacing
<- 3
K 'UrbanPop_Kcut'] <- cut(USArrests[,'UrbanPop'],K)
USArrests[,<- hcl.colors(K,alpha=.5)
Kcols boxplot(Murder~UrbanPop_Kcut, USArrests,
main='', col=Kcols,
xlab='Urban Population', ylab='')
# 4 Groups with equal numbers of observations
#Qcuts <- c(
# '0%'=min(USArrests[,'UrbanPop'])-10*.Machine[['double.eps']],
# quantile(USArrests[,'UrbanPop'], probs=c(.25,.5,.75,1)))
#USArrests[,'UrbanPop']_cut <- cut(USArrests[,'UrbanPop'], Qcuts)
#boxplot(Murder~UrbanPop_cut, USArrests, col=hcl.colors(4,alpha=.5))
The joint distribution is defined as \[\begin{eqnarray} Prob(X_{i} = x, Y_{i} = y) \end{eqnarray}\] Variables are statistically independent if \(Prob(X_{i} = x, Y_{i} = y)= Prob(X_{i} = x) Prob(Y_{i} = y)\) for all \(x, y\). Independance is sometimes assumed for mathematical simplicity, not because it generally fits data well.1
The conditional distributions are defined as \[\begin{eqnarray} Prob(X_{i} = x | Y_{i} = y) = \frac{ Prob(X_{i} = x, Y_{i} = y)}{ Prob( Y_{i} = y )}\\ Prob(Y_{i} = y | X_{i} = x) = \frac{ Prob(X_{i} = x, Y_{i} = y)}{ Prob( X_{i} = x )} \end{eqnarray}\] The marginal distributions are then defined as \[\begin{eqnarray} Prob(X_{i} = x) = \sum_{y} Prob(X_{i} = x | Y_{i} = y) Prob( Y_{i} = y ) \\ Prob(Y_{i} = y) = \sum_{x} Prob(Y_{i} = y | X_{i} = x) Prob( X_{i} = x ), \end{eqnarray}\] which is also known as the law of total probability.
For one example, Consider flipping two coins. Denoted each coin as \(k \in \{1, 2\}\), and mark whether “heads” is face up; \(X_{ki}=1\) if Heads and \(=0\) if Tails. Suppose both coins are “fair”: \(Prob(X_{i}=1)= 1/2\) and \(Prob(Y_{i}=1|X_{i})=1/2\), then the four potential outcomes have equal probabilities. The joint distribution is \[\begin{eqnarray} Prob(X_{i} = x, Y_{i} = y) &=& Prob(X_{i} = x) Prob(Y_{i} = y)\\ Prob(X_{i} = 0, Y_{i} = 0) &=& 1/2 \times 1/2 = 1/4 \\ Prob(X_{i} = 0, Y_{i} = 1) &=& 1/4 \\ Prob(X_{i} = 1, Y_{i} = 0) &=& 1/4 \\ Prob(X_{i} = 1, Y_{i} = 1) &=& 1/4 . \end{eqnarray}\] The marginal distribution of the second coin is \[\begin{eqnarray} Prob(Y_{i} = 0) &=& Prob(Y_{i} = 0 | X_{i} = 0) Prob(X_{i}=0) + Prob(Y_{i} = 0 | X_{i} = 1) Prob(X_{i}=1)\\ &=& 1/2 \times 1/2 + 1/2 \times 1/2 = 1/2\\ Prob(Y_{i} = 1) &=& Prob(Y_{i} = 1 | X_{i} = 0) Prob(X_{i}=0) + Prob(Y_{i} = 1 | X_{i} = 1) Prob(X_{i}=1)\\ &=& 1/2 \times 1/2 + 1/2 \times 1/2 = 1/2 \end{eqnarray}\]
# Create a 2x2 matrix for the joint distribution.
# Rows correspond to X1 (coin 1), and columns correspond to X2 (coin 2).
<- matrix(1/4, nrow = 2, ncol = 2)
P_fair rownames(P_fair) <- c("X1=0", "X1=1")
colnames(P_fair) <- c("X2=0", "X2=1")
P_fair## X2=0 X2=1
## X1=0 0.25 0.25
## X1=1 0.25 0.25
# Compute the marginal distributions.
# Marginal for X1: sum across columns.
<- rowSums(P_fair)
P_X1
P_X1## X1=0 X1=1
## 0.5 0.5
# Marginal for X2: sum across rows.
<- colSums(P_fair)
P_X2
P_X2## X2=0 X2=1
## 0.5 0.5
# Compute the conditional probabilities Prob(X2 | X1).
<- matrix(0, nrow = 2, ncol = 2)
cond_X2_given_X1 for (j in 1:2) {
<- P_fair[, j] / P_X1[j]
cond_X2_given_X1[, j]
}rownames(cond_X2_given_X1) <- c("X2=0", "X2=1")
colnames(cond_X2_given_X1) <- c("given X1=0", "given X1=1")
cond_X2_given_X1## given X1=0 given X1=1
## X2=0 0.5 0.5
## X2=1 0.5 0.5
Consider a second example, where the second coin is “Completely Unfair”, so that it is always the same as the first. The outcomes generated with a Completely Unfair coin are the same as if we only flipped one coin. \[\begin{eqnarray} Prob(X_{i} = x, Y_{i} = y) &=& Prob(X_{i} = x) \mathbf{1}( x=y )\\ Prob(X_{i} = 0, Y_{i} = 0) &=& 1/2 \\ Prob(X_{i} = 0, Y_{i} = 1) &=& 0 \\ Prob(X_{i} = 1, Y_{i} = 0) &=& 0 \\ Prob(X_{i} = 1, Y_{i} = 1) &=& 1/2 . \end{eqnarray}\] Note that \(\mathbf{1}(X_{i}=1)\) means \(X_{i}= 1\) and \(0\) if \(X_{i}\neq0\). The marginal distribution of the second coin is \[\begin{eqnarray} Prob(Y_{i} = 0) &=& Prob(Y_{i} = 0 | X_{i} = 0) Prob(X_{i}=0) + Prob(Y_{i} = 0 | X_{i} = 1) Prob(X_{i} = 1)\\ &=& 1/2 \times 1 + 0 \times 1/2 = 1/2 .\\ Prob(Y_{i} = 1) &=& Prob(Y_{i} = 1 | X_{i} =0) Prob( X_{i} = 0) + Prob(Y_{i} = 1 | X_{i} = 1) Prob( X_{i} = 1)\\ &=& 0\times 1/2 + 1 \times 1/2 = 1/2 . \end{eqnarray}\] which is the same as in the first example! Different joint distributions can have the same marginal distributions.
# Create the joint distribution matrix for the unfair coin case.
<- matrix(c(0.5, 0, 0, 0.5), nrow = 2, ncol = 2, byrow = TRUE)
P_unfair rownames(P_unfair) <- c("X1=0", "X1=1")
colnames(P_unfair) <- c("X2=0", "X2=1")
P_unfair## X2=0 X2=1
## X1=0 0.5 0.0
## X1=1 0.0 0.5
# Compute the marginal distribution for X2 in the unfair case.
<- colSums(P_unfair)
P_X2_unfair <- rowSums(P_unfair)
P_X1_unfair
# Compute the conditional probabilities Prob(X1 | X2) for the unfair coin.
<- matrix(NA, nrow = 2, ncol = 2)
cond_X2_given_X1_unfair for (j in 1:2) {
if (P_X1_unfair[j] > 0) {
<- P_unfair[, j] / P_X1_unfair[j]
cond_X2_given_X1_unfair[, j]
}
}rownames(cond_X2_given_X1_unfair) <- c("X2=0", "X2=1")
colnames(cond_X2_given_X1_unfair) <- c("given X1=0", "given X1=1")
cond_X2_given_X1_unfair## given X1=0 given X1=1
## X2=0 1 0
## X2=1 0 1
The joint distribution is defined as \[\begin{eqnarray} F(x, y) &=& Prob(X_{i} \leq x, Y_{i} \leq y) \end{eqnarray}\] The marginal distributions are then defined as \[\begin{eqnarray} F_{X}(x) &=& F(x, \infty)\\ F_{Y}(y) &=& F(\infty, y). \end{eqnarray}\] which is also known as the law of total probability. Variables are statistically independent if \(F(x, y) = F_{X}(x)F_{Y}(y)\) for all \(x, y\).
For example, suppose \((X_{i},Y_{i})\) is bivariate normal with means \((\mu_{X}, \mu_{Y})\), variances \((\sigma_{X}, \sigma_{Y})\) and covariance \(\rho\).
# Simulate Bivariate Data
<- 10000
N <- c(2,2) ## Means
Mu
<- matrix(c(2,-.8,-.8,1),2,2) ## CoVariance Matrix
Sigma1 <- mvtnorm::rmvnorm(N, Mu, Sigma1)
MVdat1
<- matrix(c(2,.4,.4,1),2,2) ## CoVariance Matrix
Sigma2 <- mvtnorm::rmvnorm(N, Mu, Sigma2)
MVdat2
par(mfrow=c(1,2))
## Different diagonals
plot(MVdat2, col=rgb(1,0,0,0.02), pch=16,
main='Joint', font.main=1,
ylim=c(-4,8), xlim=c(-4,8), xlab='X1', ylab='X2')
points(MVdat1,col=rgb(0,0,1,0.02),pch=16)
## Same marginal distributions
<- seq(-4,8,by=.2)
xbks hist(MVdat2[,2], col=rgb(1,0,0,0.5),
breaks=xbks, border=NA, xlab='X2',
main='Marginal', font.main=1)
hist(MVdat1[,2], col=rgb(0,0,1,0.5),
add=T, breaks=xbks, border=NA)
# See that independent data are a special case
<- 2e4
n ## 2 Indepenant RV
<- cbind( rnorm(n), rnorm(n))
XYiid ## As a single Joint Draw
<- mvtnorm::rmvnorm(n, c(0,0))
XYjoint ## Plot
par(mfrow=c(1,2))
plot(XYiid, xlab=
col=grey(0,.05), pch=16, xlim=c(-5,5), ylim=c(-5,5))
plot(XYjoint,
col=grey(0,.05), pch=16, xlim=c(-5,5), ylim=c(-5,5))
# Compare densities
#d1 <- dnorm(XYiid[,1],0)*dnorm(XYiid[,2],0)
#d2 <- mvtnorm::dmvnorm(XYiid, c(0,0))
#head(cbind(d1,d2))
The multivariate normal is a workhorse for analytical work on multivariate random variables, but there are many more. See e.g., https://cran.r-project.org/web/packages/NonNorMvtDist/NonNorMvtDist.pdf
Note Simpson’s Paradox:
Also note Bayes’ Theorem: \[\begin{eqnarray} Prob(X_{i} = x | Y_{i} = y) Prob( Y_{i} = y) &=& Prob(X_{i} = x, Y_{i} = y) = Prob(Y_{i} = y | X_{i} = x) Prob(X_{i} = x).\\ Prob(X_{i} = x | Y_{i} = y) &=& \frac{ Prob(Y_{i} = y | X_{i} = x) Prob(X_{i}=x) }{ Prob( Y_{i} = y) }. \end{eqnarray}\]
# Verify Bayes' theorem for the unfair coin case:
# Compute Prob(X1=1 | X2=1) using the formula:
# Prob(X1=1 | X2=1) = [Prob(X2=1 | X1=1) * Prob(X1=1)] / Prob(X2=1)
<- 0.5
P_X1_1 <- 1 # Since coin 2 copies coin 1.
P_X2_1_given_X1_1 <- P_X2_unfair["X2=1"]
P_X2_1
<- (P_X2_1_given_X1_1 * P_X1_1) / P_X2_1
bayes_result
bayes_result## X2=1
## 1
For plotting histograms and marginal distributions, see
Many introductory econometrics textbooks have a good appendix on probability and statistics. There are many useful statistical texts online too
See the Further reading about Probability Theory in the Statistics chapter.
The same can be said about assuming normally distributed errors, although at least that can be motivated by the Central Limit Theorems.↩︎